Python में Tic-Tac-Toe — दो खिलाड़ियों का गेम, कोड और लॉजिक

board = [" "] * 9

def show_board():
    for row in range(3):
        cells = board[row * 3:row * 3 + 3]
        print(" " + " | ".join(cells))
        if row < 2:
            print("---+---+---")

def find_winner():
    lines = [(0, 1, 2), (3, 4, 5), (6, 7, 8),
             (0, 3, 6), (1, 4, 7), (2, 5, 8),
             (0, 4, 8), (2, 4, 6)]
    for a, b, c in lines:
        if board[a] != " " and board[a] == board[b] == board[c]:
            return board[a]
    return None

def play():
    player = "X"
    moves = 0
    show_board()
    while moves < 9:
        choice = input(f"Player {player}, pick a cell (1-9): ")
        if not choice.isdigit() or not 1 <= int(choice) <= 9:
            print("Enter a number from 1 to 9.")
            continue
        index = int(choice) - 1
        if board[index] != " ":
            print("That cell is already taken.")
            continue
        board[index] = player
        moves += 1
        show_board()
        winner = find_winner()
        if winner:
            print(f"Player {winner} wins!")
            return
        player = "O" if player == "X" else "X"
    print("It's a draw!")

play()